3x^2-36x-108=0

Solution for 3x^2-36x-108=0 equation:

3x^2-36x-108=0

a = 3; b = -36; c = -108;
Δ = b2-4ac
Δ = -362-4·3·(-108)
Δ = 2592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2592}=\sqrt{1296*2}=\sqrt{1296}*\sqrt{2}=36\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36\sqrt{2}}{2*3}=\frac{36-36\sqrt{2}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36\sqrt{2}}{2*3}=\frac{36+36\sqrt{2}}{6}
$